Your feedback is highly appreciated! Let's make Vertabelo even better.
HELP - Shared template doesn't show up, but I get notification
User in the same academic account domain shares a template, I get the notification but I don't see it, what could be happening?
Please add support for Snowflake DBMS
Analytics database as a service available as a service in AWS and Azure (and GCP on the roadmap). JDBC connectivity, and ANSI-standard SQL.
Support for Snowflake Engine
Can you please add support for Snowflake Engine - https://www.snowflake.net
Mi cuenta educativa no funciona
No puedo utilizar mi cuenta educativa ni me deja eliminarla. Registré mi cuenta como estudiante con mi carnet de mi universidad y no me deja editar. El problema al parecer es porque un compañero que se creó una cuenta sin ser educativa me invitó como colaborador, pero yo no lo conozco ni tengo contacto con él. Por favor, solucionen esto, o dejenme eliminar la cuenta.
default values not quoted
I have created a table with columns containing default values and the generated sql does not quote the value, causing the following failure message:
ERROR: cannot use column reference in DEFAULT expression
I also tried quoting the value in the "Default Value" property but in both cases the SQL generated failed to quote the vallue.
auto_renew boolean NOT NULL DEFAULT FALSE,
How can i change student account to lecturer account
Could you please help me how to change my student account to lecturer account.
I would like to teach DB design using other tool than Oracle Data Modeler
Primary key generation creates errors
I have two tables, both with a column named "id" that is a SERIAL and the primary key of each.
The SQL that is generated creates a constraint to declare the primary key:
CONSTRAINT id PRIMARY KEY (id)
Using the generated SQL, the first table is created successfully.
The second table fails with the following error:
relation "id" already exists
The constraint name must be unique.
A better solution would be to suffix the primary key column with "PRIMARY KEY".
Alternatively, if you must create a constraint, prefix the name with the table name.
Alternate Index gives error - missing column
I created and alternate index and alloated a varchar(64) column.
The table has a flagged error stating that the alternate index does not have a column.
Сервис поддержки клиентов работает на платформе UserEcho